我写了这个,这是错误的语法,帮我修复它,我希望’T’是两个内连接的结果的别名.

select T.id 
from table1 
  inner join table2 on table1.x = table2.y  
  inner join table3 on table3.z = table1.w as T;

您无法直接命名连接的结果.一种选择是使用子查询：

select T.id
from (
  select *
  from table1
  inner join table2 on table1.x = table2.y
  inner join table3 on table3.z = table1.w
) T

另一种选择是子查询因子分解：

with T as (
  select *
  from table1
  inner join table2 on table1.x = table2.y
  inner join table3 on table3.z = table1.w
)
select T.id
from T